Question

Q5. Calculate the mass of sodium acetate (CH,COONa) required to make 500 mL of 0.375 molar
aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-?​

Answer 1

QUESTION :

Calculate the mass of sodium acetate $\bf [CH_3COONa]$ required to make 500 ml of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol$^{-1}$.

TO CALCULATE :

• Calculate the mass of sodium acetate $\bf [CH_3COONa]$ required to make 500 ml of 0.375 molar aqueous solution.

SOLUTION :

To calculate the mass of sodium acetate = ?

We know that,

100 ml of aqueous solution contains 0.375 moles.

$\quad \sf 1 ml \ of \ solution \ = \ \dfrac {0.375}{1000} \ moles$

$\quad : \implies \sf 50 ml \ of \ solution \ = \ \dfrac {0.375}{1000} \times 500$

$\quad : \implies \sf 50 ml \ of \ solution \ = \ \dfrac {0.375}{\not{1000}} \times {\not{500}}$

$\quad : \implies \sf 50 ml \ of \ solution \ = \ 0.1875 mol$

Now,

To find the mass of the compound.

$\qquad \red {\sf Number \ of \ moles \ = \ \dfrac {mass}{molar \ mass}}$

$\qquad : \implies \sf 0.1875 \ mol \ = \ \dfrac {mass}{82.0245}$

$\therefore \bf Mass \ of \ the \ compound \ = \ 15.37 \ g$