Question

Q5) Determine the nature of the roots of the following equations from their discriminants -
1) 2x² +5√3+6=0.

2) 3xsquare - 2x+2=0.​

Answer 1

1)2x²+5√3+6 = 0

Here a=2, b = 5√3 and c = 6

And D = b²-4ac

=> D = (5√3)²-4×2×6

=> D = 75-48

=> D = 27

Since the value of Discriminants is greater then 0 so the nature of roots are real and distinct

2) 3x²-2x+2=0

Here

a = 3 , b = -2 and c = 2

And D = b²-4ac

=> D = (-2)²-4×3×2

=> D = 4-24

=> D = -20

Since the value of Discriminant is less than 0 so equation have no real roots...