Question

Q5: f(x) = x2 - x - 2 verify and the relationship between the zeros and their coefficient​

Answer 1

Step-by-step explanation:

hope this helps you better

Answer 2

f(x)=x ² −2

=x ² −( √2 ) 2

=(x− √2 )(x+ √2 )

The zeroes off(x) are given by f(x)=0

(x− √2 )(x+ √2 )=0

(x−√ 2 )=0 or,(x+√2 )=0

x= √2 or x=− √2

Thus ,the zeroes of f(x) are α= √2 and β=− √2

Now,

Sum of the zeroes=α+β= √2 +(-√2) =0

and, −( coefficient of x )=−( 0 /1 )=0

co-efficient of x²

Therefore sum of the zeroes=−( coefficient of x )

coefficient of x ²

Product of the zeroes=α×β=

√2 ×− √¶2 =−2

and,

constant term= −2/1 =−2

coefficient of x ²