Question

Q5. Factorise: x2 + 22x + 105. Answer: A (x + 7) (x + 15) B (x-7)(x-5 C (x + 17) (x - 5) D (x + 15) (x + 7)​

Answer 1

Answer:

The correct answer is option (A) .

Step-by-step explanation:

Given expression is

   $x^2+22x+105$

Split the middle term

 $=x^2+15x+7x+105$

Group the terms

$=(x^2+15x)+(7x+105)$

Factor both the terms

$=x(x+15)+7(x+15)$

Take out the common factor

$=(x+15)(x+7)$