Q5. Factorize 2(a + 1)2
– 9(+ 1) – 5 (Hint: here you can
suppose (a + 1) as x)
(i) (2x + 1)(x – 5)
(ii) (2a + 3)(a – 4)
(iii) (2a – 1)(a + 5)
(iv) (2a – 3)(a + 4)
Answers
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5
Answer:
If you have four terms with no GCF, then try factoring by grouping.
- Step 1: Group the first two terms together and then the last two terms together.
- Step 2: Factor out a GCF from each separate binomial.
- Step 3: Factor out the common binomial.
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