Question

Q5.

Find a, b and c such that the following numbers are in AP: a,
7, b, 23 and c.​

Answer 1

Answer:

a= -1, b=15, c=31

Step-by-step explanation:

In AP, the difference between two consequent terms is constant.

So,

7-a = b-7

So a+b=14

then 23-b = b-7

So 2b = 30 , b = 15

We saw that a+b = 14 and b = 15

So a = 14-b = 14-15 = -1

Then c-23 = 23-b = 23-15 = 8 ( as b=15)

So c-23 =8 .

c = 8+23 = 31