Question

Q5. Find a cubic polynomial with sum, sum of the products of its zeroes taken two at a time and
product of its zeroes as 5,2 and -24 respectively.​

Answer 1

Step-by-step explanation:

let,

the cubic polynomial be ax^2+bx^2+cx+d

zeroes of polynomial be m,n and p

as per question,

m+n+p=5

mn+np+pm=2

mnp=-24

Now,

P(x)=k[x^3-(m+n+p)x^2+(mn+np+pm)x-mnp]

=k[x^3-(5)x^2+(2)x-(-24)]

=k[x^3-5x^2+2x+24]