Question

Q5. Find the HCF of 3y3 and 15xy.​

Answer 1

${\huge{\bold{\underline{Answer:-}}}}$

18xy,15xy3,33x2y2

18xy=2×3×3×xy

15xy3=3×5××xy3

33x2y2=3×11×x2y2

So, the common factors are 3xy.

Therefore, the H.C.F is 3xy.

Answer 2

$sch4y$

Step-by-step explanation:

Find the HCF of 3y3 and 15xy.