Math, asked by Alok776, 6 months ago

Q5: . Find the smallest square number that is divisible by each of the numbers 8, 15 and 20.​

Answers

Answered by Anonymous
4

Answer:

1, the smallest square

Answered by jyoti1997maurya
1

Answer:

answer is 3600

Step-by-step explanation:

LCM of 8,15 and 20 = 2*2*2*3*5

= 120

hence,prime factor 2,3 and 5 do not have their respective pairs. Therefore,120 is not a perfect square.

Therefore,120 should be multiple by 2*3*5 to obtain a perfect square.

hence, the required square number is

120*2*3*5 = 3600

"hope it's helpful"

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