Question

Q5. For a parallel plate capacitor, show that energy density is equal to 1/2 e° E^2
(E is the electric field between the plates)​

Answer 1

Answer:

Correct option is

B

21.6 NC

−1

Given that,

Energy density =2.1×10

−9

J/m

3

We know that,

η=

2

1

ε

0

E

2

2.1×10

−9

=

2

1

×8.85×10

−12

×E

2

E

2

=

8.85×10

−12

4.2×10

−9

E

2

=0.47×10

3

E

2

=470

E=21.6N/C

Hence, the value of the electric field in the region between the plates is 21.6 N/C