Math, asked by pranjalrailko, 10 months ago

Q5
Given that HCF (2520, 6600) = 120 and LCM (2520, 6600) = 252 k,
then find the value of k is:
(a) 165
(b) 550
(c) 990
(d) 1650

If two positive integers a and b are written as a = x3y2 and h = 773

Answers

Answered by srushtisp

2

Answer:

b

Step-by-step explanation:

HCF(a,b)*LCM(a,b)= a*b

120*252k=2520*6600

k=2520*6600/120*252

k=550

Therefore,

answer is (b) 550

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