Question

Q5. If 1 is a zero of the polynomial p(x) = ax^2 - 3(a - 1)x-1, then find the
value of a?​

Answer 1

Answer:

Step-by-step explanation:

Sorry don't know but I can suggest u to download connects app and ask your doubts there

Answer 2

QUESTION:

If 1 is a zero of the polynomial p(x) = ax^2 - 3(a - 1)x-1, then find the

value of a?

TO FIND :

VALUE OF a?

ANSWER :

As 1 is zero of the polynomial p(x).

so

p(1) = 0.

$p(x) = a {x}^{2} - 3(a - 1)x - 1$

$p(1) = a( {1})^{2} - 3(a - 1)1 - 1 \\ a - 3a + 3 - 1 = 0 \\ - 2a + 2 = 0 \\ - 2a = - 2 \\ a = 1$

FINAL ANSWER :

$a = 1$

plz Mark as brainliest