Q5. If tan0=4/3 then find the value of (2sin-cos)/(2sin+3cose)
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Answer:
since tan=4/3
on plotting a right triangle with perpendicular=4 and base is 3
we get sin=4/5
and cos=3/5
so (2sin-cos)/(2sin+3cos=
(2*4/5 -3/5) / (2*4/5 +3*3/5)
(8/5-3/5) /(8/5 + 9/5)
(5/5) / (17/5)
=5/17
so the answer is 5/17
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