Question

Q5. If the discriminant of the
equation 2x^2 - bx + 1 = 0 is 1,
then find the value of b.​

Answer 1

Step-by-step explanation:

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Answer 2

In eqn 2x²-bx+1

a = 2

b = b

c = 1

D = b² - 4ac

1 = (b)² - 4(2)(1)

1 = b² - 8

b² = -8 - 1

b² = -9

b = -√9

b = -3

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