Question

Q5.If x+y=3 and 2x+5y=12 then find the value of x and y.​

Answer 1

Answer:

Given equations are

x+y = 3

2x + 5y = 12

Since, the system has unique solution at

x = x₁ and y = y1

That means the lines intersect at only one point (x1, y₁)

By putting x = x₁ and y = y₁ in

equations, we get

X₁ +y₁ = 3...(1)

2x1 + 5y1 = 12 .... (2)

From equation (1), we have

y₁ = 3 - X1

Putting the value of y₁ in equation

⇒ 2x₁ +5 (3x₁) = 12

⇒ 2x1 + 15 - 5x₁ = 12

⇒ 2x15x1 = 12 - 15

⇒-3x1 -3

-3 3 ⇒ x₁ =

⇒ x₁ = 1

Answer 2

Answer:

1

Step-by-step explanation:

Given equations are

x+y=3

2x+5y=12

Since, the system has unique solution at x=x1 and y=y1

That means the lines intersect at only one point (x1,y1)

By putting x=x1 and y=y1 in equations, we get

x1+y1=3     ....(1)

2x1+5y1=12    ....(2)

From equation (1), we  have  

y1=3−x1

Putting the value of y1 in equation (2), 

⇒2x1+5(3−x1)=12

⇒2x1+15−5x1=12

⇒2x1−5x1=12−15

⇒−3x1=−3

⇒x1=