Q5) In the figure below, the sides AB and DC of the quadrilateral ABCD are both perpendicular to
the diagonal AC. Given that AB = 2 cm, DC =8 cm and the area of triangle ABC = 6 cm², calculate:
a. The length of AC;
b. The area of the quadrilateral ABCD
(2+2 = 4)
C
8 cm
2 cm
А
2620
D
Unsu
Answers
Answered by
6
Answer:
R.E.F. Image.
→AM=CD=10cm
BM=AB−AM
=16−10
=6cm
→ In △BMC using Pythagoras
theorem
∴BC
2
=CM
2
+BM
2
∴(10)
2
=CM
2
+(6)
2
∴CM
2
=100−36
∴CM
2
=64
∴CM=8
→CM=AD=8cm
→ Area of ABCD =
2
1
(AB+CD)×AD
=
2
1
(16+10)×8
=26×4
=104cm
2
#HAVE A NICE DAY
Answered by
3
Answer:
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