q5 please answer!!!!!
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the sum of a number and it's reciprocal is 10/3
let the required number be x
it's reciprocal = 1/x
ATQ
x + 1/x = 10/3
(x² + 1)/x = 10/3
3(x²+1) = 10x
3x² + 3 = 10x
3x² - 10x +3 = 0
3x² - 9x - x +3 = 0
3x(x-3) -1(x-3) = 0
x = 3 and x = 1/3
so the required number is 3 and it's reciprocal is 1/3
hope this will help you
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