Question

Q5.Prove that v7 is irrational.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Such questions are solved using contradiction.

Let us assume that √7 is rational, therefore we can say that,

      √7 = p/q, where q ≠ 0

√7q = p

Squaring on both sides, we get

7q^2 = p^2

If 7 divides p^2, it also divides p.

Let p = 7m

7q^2 = 49m^2

q^2 = 7m^2

If 7 divides q^2, it also divides q.

As 2 divides both p and q, therefore it contradicts are assumption that p and q are co-primes.

Hence, √7 is irrational.

(IF YOU FIND IT USEFUL, PLEASE MARK IT AS THE BRAINLIEST ANSWER)