Question

Q5. Show that the difference of a 2 digit number and it
reverse number is divisible by 9.
[ Mark -2]​

Answer 1

Answer:

Remark: The difference of a two digit number and its reversed number is exactly divisible by 9 and the quotient obtained is either the difference of the digits of the original 2-digit number or 0. yzx = 100z + 10x + y. Step-4 : Divide the answer by 111. = 111 (x + y + z) ÷ 111 = (x + y + z).

Step-by-step explanation:

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Answer 2

Answer:

Remark: The difference of a two digit number and its reversed number is exactly divisible by 9 and the quotient obtained is either the difference of the digits of the original 2-digit number or 0. yzx = 100z + 10x + y. Step-4 : Divide the answer by 111. = 111 (x + y + z) ÷ 111 = (x + y + z).

Step-by-step explanation:

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