Question

q5 tell me plz



plz plz plz​

Answer 1

this question has no real roots it has complex roots

Answer 2

Answer:

Given, polynomial = x² - 4x+ 9

In order to prove that it has no zeros, we have to show that its discriminant (D) < 0.

Here, x² - 4x + 9

a = 1, b = -4, c = 9

$\small{ \bf discriminant = b {}^{2} - 4ac}$

⇒ (-4)² - 4 * 1 * 9

⇒ 16 - 36

⇒ - 20

Here, - 20 is negative and less than 0.

Hence, the polynomial has no real zeroes.