Question

Q5.The base angle of an isosceles triangle is 10 more than twice the vertex angle. Find the valueof equalangles.​

Answer 1

Answer:

$each \: base \: angle = \frac{600}{7} \: \: \: degrees.$

Step-by-step explanation:

$let \: the \: base \: angle \: each = x \\ \\ and \: the \: vert ex \: angle = y \\ \\ \\ then \: \: \: \: x = 10y \\ \\ x + x + y = 180 \: \: by \: angle \: sum \: property \: f \: a \: triangle \\ \\ 2x + y = 180 \\ \\ solving \: these \: \\ \\ 2(10y) + y = 180 \\ \\ 21y = 180 \\ \\ y = \frac{180}{21} = \frac{60}{7 \: } \: degrees. \\ \\ x = 10( \frac{60}{7} ) = \frac{600}{7} .$