Math, asked by Anonymous, 6 hours ago

Q5: The Perimeter of an Isosceles triangle is 42 cm. The ratio of the equal side to its base is 3: 4. Find the area of the triangle.

Answers

Answered by Anonymous
1

Answer:

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Step-by-step explanation:

The ratio of the equal side to the base is 3:2.

Let the sides be 3x, 2x. Let the third =3x

Given, perimeter =32

We know that the perimeter is equal to the sum of the sides. Thus,

⇒3x+2x+3x=32

⇒8x=32

⇒x=4

⇒232=16

Thus, the sides are 12 cm, 8 cm, 12 cm

Thus, Area of the triangle =232(16−12)(16−8)(16−12)

                                          =16×4×8×4

                                          =322cm2

Answered by IxIxitzAshxIxI
1

The ratio of the equal side to the base is 3:2.

Let the sides be 3x, 2x. Let the third =3x

Given, perimeter =32

We know that the perimeter is equal to the sum of the sides. Thus,

⇒3x+2x+3x=32

⇒8x=32

⇒x=4

⇒232=16

Thus, the sides are 12 cm, 8 cm, 12 cm

Thus, Area of the triangle =232(16−12)(16−8)(16−12)

                                          =16×4×8

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