Question

Q5. The sum of three numbers in AP is -3 and their product is 8 find the numbers.
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Answer 1

Step-by-step explanation:

Answer

Solution :-

Let the number are x−y,x,x+y

Sum =−3

⇒x−y+3x+x+y=−3

⇒3x=−3

⇒x=−1

Now product =8

⇒(x−y)(x)(x+y)=8

Substituting x=−1

we get (−1−y)(−1)(−1+y)=8

(y

2

−1)=8

⇒y=±3

The no : are −4,−1,2 or 2,−1,−4

Answer 2

Answer:

a-d+a+a+d=-3

3a=-3

a=-1

(a-d).(a+d).a=8

(a^2-d^2).(-1)=8

(1-d^2).(-1)=8

-1+d^2=8

d^2=9

d=+3,-3

if +3

then AP -4,-1,2

if -3

then AP 2,-1,-4