Question

Q5. The sum of two number is 20. Thrice the larger
number exceeds four times the second member by
4. find the number.​

Answer 1

Answer:

the numbers are 6 and 14

Answer 2

given

↦(i)sumoftwonumberis90

so.

★thereforelongernumber

willbe(90−x)

★letconsidersmaller

numberbex.

★accordingtothequestion

★

3

1

ofthelongernumbersis

9morethantwicethesmallerone.

↦

3

1

(90−x)=2x+9

↦90−x=3(2x+9)

↦90−x=6x+27

↦x−6x=27−90

↦−7x=−63

↦−7x=63

↦x=

7

63

↦x=9

hence

thelongestnumberis(90−x)

=90−9=81

thissmallernumberisx=9