Question

Q5. Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third
of the sum of 6% of A and 8% of B. Find the ratio of A : B.
с
D
4:3
3:4
A
2:3
B
1:1
​

Answer 1

Question:

Two numbers a and b are such that the sum of 5% of a and 4% of b is two-third of the sum of 6% of a and 8% of  b. Find the ratio of a:b

x% of y = (x/100) × y

Given:

(5% of a) + (4% of b) = (2/3)×[(6% of a) + (8% of b)

To Find:

Ratios of A : B

SOLUTION:

Given,

(5% of a) + (4% of b) = (2/3)×[(6% of a) + (8% of b)

=> (5a/100) + (4b/100) = (2/3)×[(6a/100) + (8b/100)]

=> (5a/100) + (4b/100) = (4a/100) + (16b/300)

=> (5a/100) - (4a/100) = (16b/300) - (4b/100)

=> a[(5/100) - (4/100)] = b[(16/300) - (4/100)]

=> a(1/100) = b(4/300)

=> a = b(4/3)

=> (a/b) = (4/3)

•°• a : b = 4 : 3

Thus, the required ratio is 4 : 3.

Answer: A:B = 4:3

Answer 2

Answer:

Option B

Step-by-step explanation:

5% of A + 4% of B =2

/3 (6% of A + 8% of B)

→ 5A/100 + 4B/100 =2/3 (6A/100 + 8B/100

→ 5A + 4B  = 2/3 (6A+ 8B)

→ 15A + 12B = 12A+ 16B

→  3A = 4B

→ A/B = 4/3

→ A:B = 4:3

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                                                JENNIE