Question

Q5.
Two numbers are in the ratio 3:5. If each number is increased by 10, the ratio becomes 5:7. The
numbers are:

Answer 1

Answer:

x=15 y=25

Step-by-step explanation:

Let nos. be x and y.

x/y=3/5

So, 5x=3y or x=3/5y

(x+10)/(y+10)=5/7

7(x+10)=5(y+10)

7x+70=5y +50

Substituting x in the eqn.

21/5y -5y = 50-70

-4/5y = -20

y= (5*20)/4

y = 25

x = 3/5y = (25*3)/ 5 = 15

Answer 2

Answer:

Given :-

• Two numbers are in the ratio of 3 : 5. If each number is increased by 10, the ratio become 5 : 7.

To Find :-

• What are the numbers.

Solution :-

Let, the first number be 3x

And, the second number will be 5x

According to the question,

⇒ $\sf \dfrac{3x + 10}{5x + 10} =\: \dfrac{5}{7}$

By doing cross multiplication we get,

⇒ $\sf 5(5x + 10) =\: 7(3x + 10)$

⇒ $\sf 25x + 50 =\: 21x + 70$

⇒ $\sf 25x - 21x =\: 70 - 50$

⇒ $\sf 4x =\: 20$

⇒ $\sf x =\: \dfrac{\cancel{20}}{\cancel{4}}$

➠ $\sf\bold{\pink{x =\: 5}}$

Hence, the required numbers are,

$\mapsto$ First number :

↦ $\sf 3x$

↦ $\sf 3 \times 5$

➦ $\sf\bold{\purple{15}}$

$\mapsto$ Second number :

↦ $\sf 5x$

↦ $\sf 5 \times 5$

➦ $\sf\bold{\purple{25}}$

$\therefore$ The numbers are 15 and 25.