Question

Q5) what is pressure on a swimmer 10m below
the surface of lake? g=10m/s² and density = 1.01 x 10^5 Pa.​

Answer 1

Explanation:

given

h = 10m

g = 10m/s2

density 1.01×10^5

$p = p + pgh \\ 1.01 \times 10 {}^{5} + 1000 \times 10 \times 10$

1.98atm