Question

Q5. What will be the mole fraction of Kl if the density of 20% aqueous Kl is 1.202 gm mole
(1M)
(a) 0.0263
(b) 1.026
(c) 0.0239 (d) 0.064
per litre?
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Answer 1

Explanation:

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Answer 2

Explanation:

It is given that the density of the solution = 1.202 g mL - 1

∴Volume of 100 g solution = Mass / Density

= 100g / 1.202g mL-1

= 83.19 mL

= 83.19 × 10 - 3 L

Therefore, molarity of the solution = 20/166 mol / 83.19 × 10 - 3 L

= 1.45 M

(b) Moles of KI = 20/166 = 0.12 mol

Moles of water = 80/18 = 4.44 mol

Therefore, mole fraction of KI = Moles of KI / (Moles of KI + Moles of water)

= 0.12 / (0.12+4.44)

= 0.0263