Question

Q5.Write the greatest and the smallest 7 digit numbers you can make using the digits
3,5,7,0,1( Digits may be repeated). Also write the number names(both numbers) in
International system.​

Answer 1

Answer:

Step-by-step explanation:

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Grade 6

Mathematics

NCERT Solutions - Mathematics, Class 6

Playing With Numbers

Exercise 3.3

Question 5

Playing With Numbers | Exercise 3.3

Question 5

CHAPTERS

1. Knowing Our Numbers

2. Whole Numbers

3. Playing With Numbers

4. Basic Geometrical Ideas

5. Understanding Elementary Shapes

6. Integers

7. Fractions

8. Decimals

9. Data Handling

10. Mensuration

11. Algebra

12. Ratio and Proportion

13. Symmetry

EXERCISES

1. Exercise 3.1

2. Exercise 3.2

3. Exercise 3.3

4. Exercise 3.4

5. Exercise 3.5

6. Exercise 3.6

7. Exercise 3.7

Q5) Write the smallest digit and the greatest digit in the blank space of each of the following

numbers so that the number formed is divisible by 3 :

(a) __ 6724 (b) 4765 __ 2

Solution

Transcript

SOLUTION:

we can find the missing number by firstly finding the sum of digits of the given numbers and then subtract it from those multiple of 3, which are greater than this sum to get the smallest and greatest digits.

i) 6+7+2+4=19

multiples of 3 greater than 19 are 21,22,27,30

therefore, 21-19=2, 24-19=5, 27-19=8, 30-19=11

smallest digit=2 greatest digit=8

ii) 4+7+6+5+2=24

24 is a multiple of 3 so smallest digit is 0 greater than 24 are 27,30,33,36

27-24=3, 30-24=6, 33-24=9 36-24=12

smallest digit=0 and greatest digit=9

Answer 2

Answer:

greatest

8,5,3,1,1,0,0

smallest

0,0,1,1,3,5,8