Math, asked by shivanimadagoni1, 6 months ago

Q50 Ind the real roots of the equilon (x^4 + 1)x + (x^4+1)(x+2)=0

Answers

Answered by kundusanjay159
0

Answer:

80

Step-by-step explanation:

Let a,b,c,d be the roots of the polynomial.

So, (a+b+c+d)=−p

(abc+abd+acd+bcd)=−r

abcd=5

Now, Arithmetic Mean ≥ Geometric Mean

ie,

4

(a+b+c+d)

≥(abcd)

1/4

=5

1/4

⇒−p≥4×5

1/4

also,

4

(abc+abd+acd+bcd)

≥(abcd)

3/4

=5

3/4

⇒−r≥4×5

3/4

So, pr≥4

2

×5=80

ie, minimum value of pr=80

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