Question

Q55. If four resistors each of 1 ohm
are connected
in series, what is their effective
resistance?
​

Answer 1

Answer:

4 ohm

Explanation:

According to the given question,

R1 = R2 = R3 = R4 = R (say)

(As resistance of each resistor is same)

Where R1, R2, R3 and R4 are the resistance four resistors.

R = Resistance = 1 ohm

And we are asked to find the equivalent resistance of series combination.

We know, for series combination

• R eq = R1 + R2 + R3 + ... + Rn

Where R eq is the equivalent resistance of R1, R2, R3...Rn connected in series combination.

Similarly,

• R eq = R1 + R2 + R3 + R4

• R eq = R + R + R + R

• R eq = 4R

Putting the values we get,

• R eq = 4×1

• R eq = 4 ohm

Thus equivalent resistance of 4 resistors connected in series combination is 4 ohm.

Answer 2

$\mathbb{\huge{\boxed{Answer = 4ohm}}}$

___________________

Formula used in answer =

Rs= R1 +R2..........

(where Rs is overall resistance in series and other R1, R2 are resistance)

_______________________

Step-by-step Explanation

Resistance =1ohm, each

Number of resistance =4

Now resistance :-

R1=1ohm

R2=1ohm

R3=1ohm

R4=1ohm

Put all these values in formula

Rs = R1+ R2+R3 + R4

Rs=1+1+1+1

Rs = 4 ohm

Rs = 4 ohm

More information :-

• In series resistance are always added simply.
• In parallel resistance are reciprocated and then added.

Formula of parallel resistance is :-

1/Rp = 1/R1 + 1/R2........

:-)