Q6. 2 4 6 5 m 7 8 In the above figure, I is parallel to m and a transversal t cuts them. If Z1 = 70°, find the measure of each of the remaining marked angles.
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It is given that ∠1=120
o
from the figure we know that ∠1 and ∠2 form a linear pair of angles
so it can be written as
∠1+∠2=180
o
by substituting the values
120
o
+∠2=180
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∠2=60
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from the figure we know that ∠1 and ∠3 are vertically opposite angles
we get
∠1=∠3=120
o
from the figure we know that ∠2 and ∠4 are vertically opposite angles
we get
∠2=∠4=60
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it is given that l∥m and t is a transversal
so the corresponding angles according to the figures is written as
∠1=∠5=120
o
∠2=∠6=60
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∠3=∠7=120
o
∠4=∠8=60
o
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