Question

Q6.

A box contains three blue balls and four red balls. Another identical box contains two blue balls and five red balls. One ball is picked at random from one of the two boxes and it is red. The probability that it came from the first box is
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Answer 1

Answer:

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Step-by-step explanation:

Let A be the event of choosing a ball from first box( which contains 4 blue, 2 green, 3 red balls)

Let A' be the event of choosing a ball from second box

Let B be the event of choosing a blue ball

Then,

P(B)= P(A)*P(B|A) + P(A')*P(B|A')

P(B)= 1/2*(4/9) + 1/2*(5/12)

P(B)= 0.4305

Hence, probability of choosing a blue ball is 0.4305.

Answer 2

Answer:

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