Question

Q6. A conical tent is 3m high and
diameter of base is 8m. find its slant
height​

Answer 1

Answer:

l=√73 m

Step-by-step explanation:

l=$\sqrt{(h)^{2}+(b)^{2} }$

l=$\sqrt{(3)^2+(8)^2}$

l=$\sqrt{9+64}$

l=$\sqrt{73} m$

Answer 2

QUESTION:

A conical tent is 3m high and

diameter of base is 8m. find its slant

height.

ANSWER:

Height of conical tent = 3 m

diameter of base = 8 m

We know that :

$diameter = 2 \times radius$

SO radius of the base will be 4 m.

To find the slant height we use the formula :

$\sqrt{ {radius}^{2} + {height}^{2} }$

SO ,

$l = \sqrt{ {4}^{2} + {3}^{2} } \\ l = \sqrt{16 + 9} \\ l = \sqrt{25} \\ l = 5m$

FINAL ANSWER :

SLANT HEIGHT =5 M

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