Question

Q6
A hot air balloon of mass of 300
kg is descending at a constant
acceleration of 2 m/s2. When a
mass m is removed from the hot
air balloon, it starts rising with
the same acceleration 2 m/s2.
Assuming that its volume does
not change, If the value of mis
10p kg. Then the value of p is
20
10
15
5​

Answer 1

Answer:

20 is right answer bro OK good night

Answer 2

Answer:

(B)The value of p is 10

Explanation:

Given that,

Mass of the balloon(m)=300kg

Acceleration with which balloon descends is

$a = 2ms {}^{ - 2}$

After a mass m is removed from the balloon it starts rising with same acceleration

Let the thrust on the balloon be T.From free body diagram we have

$300(g )- T = 300a$

Since mass m is removed we have the relations

$T - (300 - m)g = (300 - m)a \\ = >T - 300g + mg = 300a - ma \\ = > - 300a + mg = 300a - ma \\ = > 600a = m(a + g) \\ = = > m = \frac{600a}{a + g} = \frac{600 \times 2}{10 + 2} \\ = 100kg$

Hence the mass removed is 100kg.But given that the mass removed is '10p'kg.Therefore,

$10p = 100 = > p = 10$

Hence,the value of p is 10

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