Q6. A is twice as old as B. Five years ago A was 3 times as old as B.
Find their present ages
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let b's age be X
and a's age be 2x .
Five years ago a was 3 times b's age at that time = 3(x-5)
b's age at that time = x-5
And a's age is also 2x-5 at that time
So, 3(x-5)=2x-5
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