Math, asked by Hamzaking123, 1 month ago

Q6. A number is divided into two parts, such that one part is 10 more than the other.
If the two parts are in the ratio 5:3, find the number and the two parts.​

Answers

Answered by yashupadhyay100
2

Step-by-step explanation:

LETS TAKE 5:3 PARTS IN RATIO AS 5x and 3x

So

1Number = Divided in 2 parts

and the first part = 5x and second part 3x

we see that 5x = 3x + 10

5x - 3x = 10 = 2x = 10 = x =

if x = 5 then the parts are

5(5),5(3)=25,15

the two parts are 25 and 15

and the number is 25+15 = 40

Answered by smitsham
1

Answer:

Since the two parts are in the ratio 5:3, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40.

Step-by-step explanation:

I hope this helps you

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