Question

Q6: A scooter moving at speed of 10 m/s is stopped by applying brakes which produces an acceleration of -0.5 m/s2. How much Distance is travelled by the scooter, and how much time it takes to stop?

Answer 1

$\large \dag$ Question :-

A scooter moving at speed of 10 m/s is stopped by applying brakes which produces an acceleration of -0.5 m/s2. How much Distance is travelled by the scooter, and how much time it takes to stop ?

$\large \dag$ Answer :-

$\red\dashrightarrow\underline{\underline{\sf  \green{Distance   \: Covered \: is \: 120\: m }} }$

$\red\dashrightarrow\underline{\underline{\sf  \green{Time   \: Taken \:  to  \: Stop \: is \: 100\: m }} }$

$\large \dag$ Step by step Explanation :-

Here we have :

• Initial Velocity = u = 10 m/s

• Acceleration = a = - 0.5 m/s²

• Final Velocity = v = 0 m/s

⇝ Calculating Time Taken to stop :-)

❒ We Have 1st Equation of Motion as :

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{   \blue{  v = u + at}}}}$

⏩ Applying 1st Equation of Motion ;

$:\longmapsto \rm 0 = 10 + ( - 0.5) \times t$

$:\longmapsto \rm 0 = 10 - 0.5t$

$:\longmapsto \rm 0.5t = 10$

$:\longmapsto \rm t = \frac{10}{0.5}$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf t = 20 \: s} }}}$

Therefore,

$\underline{\pink{\underline{\frak{\pmb{\text Time \: \text Taken \:to \:stop =20 \: s }}}}}$

⇝ Calculating Required Distance :-)

❒ We Have 2nd Equation of Motion as :

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{   \blue{ s = ut + \frac{1}{2} at {}^{2} }}}}$

⏩ Applying 2nd Equation of Motion ;

$:\longmapsto \rm s = 10 \times 20 + \frac{1}{2} \times ( - 0.5) \times {20}^{2}$

$:\longmapsto \rm s = 200 - 100$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf s = 100 \: m} }}}$

Therefore,

$\underline{\pink{\underline{\frak{\pmb{Distance \: Covered \: b \text y \: \text Scooter =100 \: m }}}}}$

Answer 2

QUESTION-:

A scooter moving at speed of 10 m/s is stopped by applying brakes which produces an acceleration of -0.5 m/s². How much Distance is travelled by the scooter, and how much time it takes to stop?

EXPLANATION-:

• Initial velocity(u)=10 m/s
• Final velocity(v)=0 m/s
• Acceleration(a)=-0.5 m/s²
• Distance(s)=??
• Time=??

Using third equation of kinematics -:

$\boxed{\bigstar\bf\; v^2=u^2+2as \;\bigstar}$

Putting values-:

→(0)²=(10)²+2(-0.5×s)

→0=100-s

→s=100 m

So the distance is 100 metres

Now let's calculate the time ,using 1st equation of kinematics-:

$\boxed{\bigstar\bf\;v=u+at\;\bigstar}$

Putting values-:

→0=10-0.5t

→t=10/0.5

→t=20 s

Therefore,

Distance=100 m and time is 20 s

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