Question

Q6 A side of square with

a side of square with
area X2
+6x + 9 square units
is​

Answer 1

Step-by-step explanation:

4x² + 12x + 9

=> ( 2x )² + 2( 2x × 3 ) + 3²

=> ( 2x + 3 )²

=> Area of square = ( 2x + 3 )²

=> side² = ( 2x + 3 )²

=> side = 2x + 3 units

Answer 2

Answer:

The Area of square A is x2+6x+9=(x+3)2

⇒ The Area of square A is (x+3)×(x+3)

⇒(x+3) is a side of square A

The Area of square B is 4x2–20x+25=(2x−5)2

⇒ The Area of square B is (2x−5)×(2x−5)

⇒(2x−5) is a side of square B

Also, we are given that sum of perimeters of both squares is 52

Perimeter of square A is 4×(x+3)

Perimeter of square B is 4×(2x−5)

⇒PA+PB=52

⇒4x+12+8x−20=52

⇒12x−8=52

⇒12x=60

⇒x=5

Step-by-step explanation:

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