Question

Q6. An object is placed 15 cm from a convex mirror of radius of curvature 60 cm. Find the position of image and its magnification.

Answer 1

Hey mate!

Here's your answer!!

Focal length,
f=Radius of curvature /2=60/2=+30 cm

Object distance,
u=-15 cm

Using mirror formula

1/v + 1/u = 1/f

or 1/v=1/f- 1/u

1/v=1/30-(-1/15)

Image distance, v=10 cm

Now, magnification m=-v/u

m=-(10/(-15)=10/15=0.67

Hope it helps you!

Answer 2

Explanation :

Focal length of the convex lens, $f=\dfrac{-R}{2}=\dfrac{-60\ cm}{2}=-30\ cm$

Object distance, $u=-15\ cm$

Using mirror's equation :

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{-1}{30}-\dfrac{1}{15}$

$v=-10\ cm$

The image is formed at a distance of 10 cm in front of mirror.

Magnification, $m=\dfrac{-v}{u}$

$m=\dfrac{-(-10)}{-15}$

$m=-0.67$

Hence, this is the required solution.