Question

Q6 Arithmatic mean between 1/a and 1/b ?​

Answer 1

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Answer 2

The correct answer is  $\frac{a+b}{2ab}$.

Given: The variables for which mean is to be calculated = $\frac{1}{a}$ and $\frac{1}{b}$.

To Find: Arithmetic mean.

Solution:

Arithmetic mean of two quantities x and y = $\frac{x+y}{2}$.

Arithmetic mean of  $\frac{1}{a}$ and $\frac{1}{b}$ will be = $\frac{\frac{1}{a}+\frac{1}{b} }{2}$

= $\frac{\frac{a+b}{ab} }{2}$

= $\frac{a+b}{2ab}$

Hence, the arithmetic mean of  $\frac{1}{a}$ and $\frac{1}{b}$  is  $\frac{a+b}{2ab}$.

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