Question

Q6.  Calculate the force exerted by the brakes on the motorcar which is moving with a velocity of 72 km/h and takes 5 s to stop after the application of brakes. Mass of the motorcar along with the passengers is 800 kg.

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Answer 1

Answer:

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Explanation:

ANSWER

Force=mass*acceleration

f=m×

t

v−u

f=1000×

4

0−108×

18

5

=1000×(−7.5)

∴f=−7500N

opposing force is denoted by negative sign.

Answer 2

Given :-

☄ lnitial velocity, u = 72km/hr = 20m/s

☄ finial Velocity, v = 0m/s

☄ time taken, t = 5s.

☄ Mass, m = 800kg.

To find :-

the force exerted by the brakes on the motorcar

Solution :-

Using equation of motion .i.e.,

➠ v = u + at

➠ 0 = 20 + (a)(5)

➠ a = -20/5

➠ a = -4m/s²

|| -ve sign detects that the body is Retarding ||

we know that,

➠ F = ma

➠ F = (800)(4)

➠ F = 3200N

thus, the force exerted by the brakes on the motorcar is 3200N.

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