Question

Q6. Find the Pythagorean triplet whose largest member is 10.​

Answer 1

Answer:

pythagorean triplet = 6, 8, 10

Answer 2

If, 10 is the largest member , then it must be the hypotenuse.

Now, according to Pythagoras Theorem:-

(Altitude)² + (Base)² = (Hypotenuse)²

Let altitude be x and base be y.

So, x² + y² = 10²

x² + y² = 100

Now, we have to find two numbers such that sum of their squares is 100 and less than 10.

So, let us take x = 6 and y = 8.

Putting these values in the equation formed.

6² + 8² = 100

36 + 64 = 100

100 = 100

So, our equation is satisfied.

Hence, the Pythagorean Triplet so founded is :- (6 , 8 and 10)