Question

Q6. If 1 is a zero of the polynomial P(x) = ax^2 - 3(a-1)x-1, then find the value of a​

Answer 1

Answer:

Value of a is 1

Step-by-step explanation:

1 is the zero of the polynomial

So x=1

Substituting,

P(1)=a(1)² - 3(a-1)1 - 1 = 0

a-3a+3-1=0

-2a +2=0

-2a=-2

a=-2/-2

a=1

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