Math, asked by kushanshah, 9 months ago

Q6 In a group of 72 students, 47 have background is electronics, 59 have background in Mathematics & 42 have background in both the subjects. How many subjects do not have background in any of the subjects?

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Answers

Answered by IshitaAgarwal05
3

Answer:

Q6 1) 8

Q7 2) Finite Set

Step-by-step explanation:

Q6

Students whose background is electronics = 47

Students whose background is mathematics = 59

Students whose background is both electronics & mathematics = 42

Total no. of students = 72

So, the no. of students do not have background in any of the subjects --->

=> 72 - 47 - 59 + 42 = 114 - 106 = 8

Q7

=> x^2 - 3x + 2 = 0

=> x^2 - x - 2x + 2 = 0

=> x(x-1) - 2(x-1) = 0

=> (x-2)(x-1) = 0

=> x = 1,2

Since, the no. of elements of this set of this element is only 2,

Therefore, this is a finite set.

Hope this helps.....

Answered by saman19patel96
0

Answer:

If 11 people are taking both courses, this means 51-11 or 40 are taking kickboxing only and 25-11 or 14 are taking yoga only. The number of people taking at least one course, therefore, is 40 + 14 + 11 = 65. The 83 members minus the 65 that are taking courses leaves 18 who are not taking any courses.

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