Q6 In a group of 72 students, 47 have background is electronics, 59 have background in Mathematics & 42 have background in both the subjects. How many subjects do not have background in any of the subjects?
Answers
Answer:
Q6 1) 8
Q7 2) Finite Set
Step-by-step explanation:
Q6
Students whose background is electronics = 47
Students whose background is mathematics = 59
Students whose background is both electronics & mathematics = 42
Total no. of students = 72
So, the no. of students do not have background in any of the subjects --->
=> 72 - 47 - 59 + 42 = 114 - 106 = 8
Q7
=> x^2 - 3x + 2 = 0
=> x^2 - x - 2x + 2 = 0
=> x(x-1) - 2(x-1) = 0
=> (x-2)(x-1) = 0
=> x = 1,2
Since, the no. of elements of this set of this element is only 2,
Therefore, this is a finite set.
Hope this helps.....
Answer:
If 11 people are taking both courses, this means 51-11 or 40 are taking kickboxing only and 25-11 or 14 are taking yoga only. The number of people taking at least one course, therefore, is 40 + 14 + 11 = 65. The 83 members minus the 65 that are taking courses leaves 18 who are not taking any courses.