Question

Q6. Points (6,4), (5,2) and ( 7,2) are the vertices of (A) equilateral triangle (B) isosceles triangle kyscalene triangle (D) none​

Answer 1

Let ABC be the triangle A(5,−2),B(6,4),C(7,−2)

By distance formula

AB=(5−6)2+(−2−4)2=(−1)2+(−6)237

BC=(6−7)2+(4−(−2)2=(−1)2+(6)2=37

CA=(7−5)2+(−2−(−2))2=(2)2+0=2

Since AB=BC=37

Hence (5,−2),(6,4) & (7,−2) are vertices of isosceles triangle.

Answer 2

Step-by-step explanation:

let the triangle abc having vertex a(6,4) b(5,2) and c(7,2)

using distance formula

X = √ (x2-x1)² + (y2-y1)²

ab= √(6-5)²+(4-2)² = √5

bc = √(5-7)²+(2-2)² = √4=2

ac= √ (6-7)²+(4-2)² = √5

here ab = ac but not equal to bc

it means the given coordinates is of an isosceles triangle

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