Question

Q6 Sum of the digits of a two digit number is 11. The given number is less than the number
obtained by interchanging the digits by 9. Find the number.
1.​

Answer 1

Answer:

Here's ur answer....

Step-by-step explanation:

It is a two digit number,

So, one's digit=x

ten’s digit=y

given, x+y =11. - 1st equation

10y+x- two digit format

10y+x-(10x+y)=9. [ Given that the given no.is less than the number obtained by interchanging the digits by 9]

10y+x-10x-y=9

9y-9x=9

y-x=1.

-x+y= 1. - 2nd equation

Solving equation 1 and 2,

x+y=11

-x+y=1

_______

2y=12

y=12/2

y=6

Substituting y=6in equation 1,

x+y=11

x+6=11

x=11-6

x=5

x=5;y=6

Ten’s digit format= 10y+x

=10(6)+5

=65

The required two digit no.is 65

Hope it helps.....

Plz mark as brainliest!!!!

For class 8

Given, the sum of 2-digit number is 9

Let the unit digits of the number is x

then the tenth digit of the number is 9 - x

Now original number = 10(9-x) + x = 90 - 10x + x = 90 - 9x

Now digits of the numbers are interchanged.

So, unit digit = 9 - x

and tenth digit = x

The number = 10x + 9 - x = 9x + 9

According to the question,

9x + 9 = 90 - 9x + 27

=> 9x + 9 = 117 - 9x

=> 9x + 9x = 117 - 9

=> 18x = 108

=> x = 108/18

=> x = 6

So, the unit digit of the number = 6

and tenth digit of the number = 9 - x = 9 - 6 = 3

So, the required number = 36

U could refer this example