Question

Q6. The product of two
fractions is 3/4 and their
quotient is 6/18. If the
denominator of one is 1/3 of
the other's numerator, then
find the pair of fractions?​

Answer 1

Let A = x/y, and B be two fractions

It is given that A*B = 3/4

Therefore x/y * B = 3/4

B = 3y/4x

Therefore, A = x/y and B = 3y/4x

It is given that A/B = (x/y) / (3y/4x) = 6/18

Therefore x/y * 4x/3y = 6 /18

Therefore 4x2/3y2 = 6/18

x2/y2 = 18/(4*18)

Therefore, x2/y2 = ¼

x/y = 1/2

B = 3y/4x = 3/4 (1/(x/y)) = 3/4 [1/(1/2)] = 6/4

Therefore A = 1/2 and B = 3/2