Question

Q6.Train starting from rest attain a velocity of 108km/h in 3 minute. Assuming that acceleration to be

uniform find a) acceleration b)distance travelled by train for attaining this velocity.​
if any of u give ans I will mark his her as a brainliest

Answer 1

Explanation: In this question,

u = initial velocity = 0 (at rest)

v = 108 km/hr = (108*5/18) m/s = 30m/s

t = 3 min = 3*60 = 180 sec

For uniform acceleration, we can use the equations of motion directly,

=> v = u + at

=> 30 = 0 + a(180)

=> 30/180 = a

=> 1/6 m/s² = a

In km/hr², acceleration is 2160 km/hr².

Moreover, for distance:

=> S = ut + ½ at²

=> S = 0 + ½ (1/6)(180)²

=> S = 270 m or 2.7 km

Answer 2

Answer:

Given :-

Train starting from rest attain a velocity of 108km/h in 3 minute. Assuming that acceleration to be uniform

To Find :-

Acceleration

Distance travelled

Solution :-

We know that

1 km/h = 5/18 m/s

So,

108 km/h = 180 × 5/18 = 30 m/s

Converting min to sec

1 min = 60 sec

3 min = 180 sec

Now

a = v - u/t (1 st equation of motion)

a = 30 - 0/180

a = 30/180

a = 3/18

a = 1/6 m/s²

now

v² - u² = 2as (3rd equation of motion)

(30)² - (0)² = 2(1/6)(s)

900 - 0 = 1/3s

900 × 3 = s

2700 = s

Distance may be also written as

1 km = 1000 m

2700 m = 2700/1000 = 27/10 = 2.7 km

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