Q6.Train starting from rest attain a velocity of 108km/h in 3 minute. Assuming that acceleration to be
uniform find a) acceleration b)distance travelled by train for attaining this velocity.
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Answers
Explanation: In this question,
u = initial velocity = 0 (at rest)
v = 108 km/hr = (108*5/18) m/s = 30m/s
t = 3 min = 3*60 = 180 sec
For uniform acceleration, we can use the equations of motion directly,
=> v = u + at
=> 30 = 0 + a(180)
=> 30/180 = a
=> 1/6 m/s² = a
In km/hr², acceleration is 2160 km/hr².
Moreover, for distance:
=> S = ut + ½ at²
=> S = 0 + ½ (1/6)(180)²
=> S = 270 m or 2.7 km
Answer:
0.16m/s^2,5400m
Step-by-step explanation:
given,
u=0
v=108km/h=108*5/18=30m/s
t=3m=180s
a)acceleration=v-u/t=30-0/180=30/180=1/6=0.16m/s^2
b)distance travelled=velocity*time
=30*180
=5400m
here we will assume train is travelling on a straight path as no such is given therefore linear displacement= distance travelled.