Question

Q6.Train starting from rest attain a velocity of 108km/h in 3 minute. Assuming that acceleration to be

uniform find a) acceleration b)distance travelled by train for attaining this velocity.​
if any of u give ans I will mark his her as a brainliest​

Answer 1

Explanation: In this question,

u = initial velocity = 0 (at rest)

v = 108 km/hr = (108*5/18) m/s = 30m/s

t = 3 min = 3*60 = 180 sec

For uniform acceleration, we can use the equations of motion directly,

=> v = u + at

=> 30 = 0 + a(180)

=> 30/180 = a

=> 1/6 m/s² = a

In km/hr², acceleration is 2160 km/hr².

Moreover, for distance:

=> S = ut + ½ at²

=> S = 0 + ½ (1/6)(180)²

=> S = 270 m or 2.7 km

Answer 2

Answer:

0.16m/s^2,5400m

Step-by-step explanation:

given,

u=0

v=108km/h=108*5/18=30m/s

t=3m=180s

a)acceleration=v-u/t=30-0/180=30/180=1/6=0.16m/s^2

b)distance travelled=velocity*time

                               =30*180

                               =5400m

here we will assume train is travelling on a straight path as no such is given therefore linear displacement= distance travelled.